Logarithm theorems

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Question język polski Answer język polski
log_a b= c
Definition
log b; ln b
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a^c= b
10^c= b; e^c= b
log_a x*y=
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log_a x + log_a y
log_a x/y=
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log_a x - log_a y
Warunki dla log_a b= c
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a≠0 ʌ a, b>0
log_a x^y=
Wyciągnięcie potęgi.
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y*log_a x
log_a b=
Wprowadzenie nowej podstawy.
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log_c b/log_c a
a^log_b c=
a^(log_a b)=
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c^log_b a
b
log_a 1/x=
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-log_a x
log_[1/a] x=
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-log_a x
log_a 1=
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0
log_a a=
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1
log_a \s|x\=
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1/s* log_a x
1/(log_a b)=
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log_b a
log_a b * log_b c=
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log_a c
log_a^c b=
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1/c* log_a b

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