Deriviatives

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Question język polski Answer język polski
[f(g(x))]'=
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f'(g(x))*g(x)'
x'=
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1
c'=
c is constant
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0
(ax+b)'=
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a
(1/x)'
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-1/x²
(x^n)'
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nx^[n-1]
[c*f(x)]'
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c*f'(x)
[f(x)+g(x)]'=
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f'(x)+g'(x)
[f(x)-g(x)]'=
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f'(x)-g'(x)
[f(x)*g(x)]'=
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f'(x)*g(x) +f(x)*g'(x)
[f(x)/g(x)]'=
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[f'(x)*g(x) -f(x)*g'(x)] / [g(x)]²
f'(x_0)=
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lim_[h→0]_ [f(x_0 +h) -f(x_0)] / h

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